Changed regex to reference count internal structure instead of cloning because it too way too long. Added terminal decorators to grammer and lexer
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@@ -5,13 +5,19 @@ import vector
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import util
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fun lexer(regs: vector::vector<regex::regex>): lexer {
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return lexer(regs.map( fun(reg: regex::regex): util::pair<string::string, regex::regex> {
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return util::make_pair(reg.regexString,reg)
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}))
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}
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fun lexer(regs: vector::vector<util::pair<string::string, regex::regex>>): lexer {
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var toRet.construct() :lexer
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regs.for_each( fun(reg: regex::regex) toRet.add_regex(reg); )
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regs.for_each( fun(reg: util::pair<string::string, regex::regex>) toRet.add_regex(reg); )
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return toRet
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}
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obj lexer (Object) {
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var regs: vector::vector<regex::regex>
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var regs: vector::vector<util::pair<string::string, regex::regex>>
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var input: string::string
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var position: int
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fun construct(): *lexer {
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@@ -33,11 +39,17 @@ obj lexer (Object) {
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destruct()
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copy_construct(&old)
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}
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fun add_regex(newOne: regex::regex) {
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fun add_regex(name: string::string, newOne: regex::regex) {
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regs.add(util::make_pair(name,newOne))
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}
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fun add_regex(newOne: util::pair<string::string,regex::regex>) {
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regs.add(newOne)
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}
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fun add_regex(newOne: regex::regex) {
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regs.add(util::make_pair(newOne.regexString, newOne))
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}
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fun add_regex(newOne: *char) {
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regs.add(regex::regex(newOne))
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regs.add(util::make_pair(string::string(newOne), regex::regex(newOne)))
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}
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fun set_input(in: string::string) {
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input = in
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@@ -45,8 +57,8 @@ obj lexer (Object) {
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fun next(): symbol::symbol {
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if (position >= input.length())
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return symbol::symbol("$EOF$", true)
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var max = regs.map(fun(reg: regex::regex): util::pair<int, string::string> {
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return util::make_pair(reg.long_match(input.slice(position, -1)), reg.regexString); })
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var max = regs.map(fun(reg_pair: util::pair<string::string,regex::regex>): util::pair<int, string::string> {
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return util::make_pair(reg_pair.second.long_match(input.slice(position, -1)), reg_pair.first); })
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.max(fun(first: util::pair<int, string::string>, second: util::pair<int, string::string>): bool
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{ return first.first < second.first; })
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if (max.first < 0)
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