miloignis/kraken
1
0
Fork 0
Code Issues Pull Requests Packages Projects Releases Wiki Activity

Fix substr() bug when the Lexer consumes all the input at once.

Browse Source
This commit is contained in:
Jason Orendorff
2013-10-27 00:00:55 -07:00
parent 0c50ad4197
commit 4d156fa743
1 changed files with 14 additions and 4 deletions
Download Patch File Download Diff File Expand all files Collapse all files

18
src/Lexer.cpp
View File

@@ -24,13 +24,13 @@ void Lexer::addRegEx(std::string regExString) {
}
Symbol Lexer::next() {
//std::cout << "Current at is \"" << input.substr(currentPosition,input.length()-1) << "\" currentPos is " << currentPosition << " out of " << input.length() <<std::endl;
//std::cout << "Current at is \"" << input.substr(currentPosition) << "\" currentPos is " << currentPosition << " out of " << input.length() <<std::endl;
//If we're at the end, return an eof
if (currentPosition >= input.length())
return Symbol("$EOF$", true);
int longestMatch = -1;
RegEx* longestRegEx = NULL;
std::string remainingString = input.substr(currentPosition,input.length()-1);
std::string remainingString = input.substr(currentPosition);
for (std::vector<RegEx*>::size_type i = 0; i < regExs.size(); i++) {
//std::cout << "Trying regex " << regExs[i]->getPattern() << std::endl;
int currentMatch = regExs[i]->longMatch(remainingString);
@@ -42,11 +42,11 @@ Symbol Lexer::next() {
if (longestRegEx != NULL) {
std::string eatenString = input.substr(currentPosition, longestMatch);
currentPosition += longestMatch;
//std::cout << "Current at is \"" << input.substr(currentPosition,input.length()-1) << "\" currentPos is " << currentPosition <<std::endl;
//std::cout << "Current at is \"" << input.substr(currentPosition) << "\" currentPos is " << currentPosition <<std::endl;
return Symbol(longestRegEx->getPattern(), true, eatenString);
} else {
//std::cout << "Found no applicable regex" << std::endl;
//std::cout << "Remaining is ||" << input.substr(currentPosition,input.length()-1) << "||" << std::endl;
//std::cout << "Remaining is ||" << input.substr(currentPosition) << "||" << std::endl;
return Symbol();
}
}
@@ -92,5 +92,15 @@ void Lexer::test() {
assert(lex.next() == Symbol());
}
// Lexer can consume all the input at once.
{
Lexer lex;
lex.addRegEx("xyzzy");
lex.setInput("xyzzy");
s = lex.next();
assert(s.getName() == "xyzzy" && s.getValue() == "xyzzy");
assert(lex.next() == Symbol("$EOF$", true));
}
std::cout << "Lexer tests passed\n";
}