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Initial work for functions as values. Actually works, but you can't write out the type and thus can only declare function pointer variables with type inference.

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Nathan Braswell
2015-05-18 04:46:03 -04:00
parent 65fd2ed9b7
commit 911b25f78b
8 changed files with 172 additions and 111 deletions
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6
include/Type.h
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@@ -14,7 +14,7 @@ class ASTData;
#include "ASTData.h"
#include "util.h"
enum ValueType {none, template_type, template_type_type, void_type, boolean, integer, floating, double_percision, character };
enum ValueType {none, template_type, template_type_type, void_type, boolean, integer, floating, double_percision, character, function_type };
class Type {
@@ -25,6 +25,8 @@ class Type {
Type(NodeTree<ASTData>* typeDefinitionIn, int indirectionIn = 0);
Type(NodeTree<ASTData>* typeDefinitionIn, std::set<std::string> traitsIn);
Type(ValueType typeIn, NodeTree<ASTData>* typeDefinitionIn, int indirectionIn, std::set<std::string> traitsIn);
Type(ValueType typeIn, NodeTree<ASTData>* typeDefinitionIn, int indirectionIn, std::set<std::string> traitsIn, std::vector<Type*> parameterTypesIn, Type* returnTypeIn);
Type(std::vector<Type*> parameterTypesIn, Type* returnTypeIn);
Type(ValueType typeIn, NodeTree<Symbol>* templateDefinitionIn, std::set<std::string> traitsIn = std::set<std::string>());
~Type();
bool const operator==(const Type &other)const;
@@ -42,6 +44,8 @@ class Type {
NodeTree<Symbol>* templateDefinition;
std::map<std::string, Type*> templateTypeReplacement;
std::set<std::string> traits;
std::vector<Type*> parameterTypes;
Type *returnType;
private:
int indirection;
};